manu de hanoi wrote:Can you explain how the siphoning you mention works on a batch still ? i'd like to understand. Now that you mention it, since there will be a long, 8 mm pipe connected to the distillate output, i'm afraid the vapors will be pulled in the condenser too hard ..... Perhaps drilling a vent would help...Could close the vent if output is too weak.
Hmm well on a classic VM batch still the flow of product vapour is is pulled down through the product condenser by gravity, since ethanol vapour is heavier than air. At the end of the run, when vapour finally contains enough water, it will be lighter than air, reducing this effect, minimising product takeoff, until it finally stops if the still is properly tuned.
I think you won't need an extra vent to minimise output, use the valve instead.
DestructoMutt, this effect is only present in a classic VM which is enough open in the top and in the end of a (tall) Leibig condenser not to allow for any pressure differences. The law of physics i call is a simple one, gravity.
Imagine a vertical tube, filled with a gas heavier than air, open in both ends. What will happen? The gas will slowly flow down through the tube. Now imagine the same tube fillled with a gas lighter than air. The gas will rise.
Now, add a condenser in each one of the ends, still very open, and a connection to a boiler/column somewhere in the middle of this tube adding more gas. The amount of gas has to be less than or equal to the gravity forced flow in the tube. Make sure the condensate from the upper condenser flows back into the column, also by gravity.
If the gas is lighter than air (steam) it will condense in the upper condenser and reflux into the column. If its heavier (ethanol) it will flow down and condense as product.
And please note I'm _not_ suggesting that a mixture of water and ethanol vapour will separate, they wont.
Now, here's the tricky part:
Add a valve in the tube right below the inlet. Close this valve just enough to let the flow of vapour pulled down by gravity be approximately 1/10 of the total vapour entering the tube. Now 9/10 of the vapour will be forced to rise to the reflux condenser, condense and return to the column as reflux.
Now imagine, with the same power and valve settings, the vapour containing more and more water, and less and less ethanol, it will finally be lighter than air. What will happen?
Since the path up to the reflux condenser is in practice unrestricted, all vapour will head to it, and no vapour will be pulled down, by gravity, to the restricted (by the valve) path to the product condenser. Full reflux.
Of course if the amount of vapour leaving the column is large enough, the tube and reflux condenser will act as a restriction, killing this effect by introducing an overpressure just above the valve.
So, a poorly contructed or run VM vill not have this effect.
I think.