Home Distiller

Found this today. Table 1 and Table 4 from TTB turned into Excel calculator available here:
https://miller.engineering.ucdavis.edu/resources

Table 1 corrects proof and tralle hydrometer (alcometer) calibrated to 60F to any temperature from 0-100F.
Table 4 is spirit volume calculated from weight and proof. This is the one I looked for a few months ago and was not able to find.

I've been using the paper version of table 4 to determine volume of spirit contained in my Badmo barrels. I take a tare weight of the barrel wet and empty before I fill it, then can easily determine current volume based on current weight and ABV.

Homebrewer11777 wrote: ↑Tue Sep 17, 2024 5:32 am Found this today. Table 1 and Table 4 from TTB turned into Excel calculator available here:
https://miller.engineering.ucdavis.edu/resources

Table 1 corrects proof and tralle hydrometer (alcometer) calibrated to 60F to any temperature from 0-100F.
Table 4 is spirit volume calculated from weight and proof. This is the one I looked for a few months ago and was not able to find.

I've been using the paper version of table 4 to determine volume of spirit contained in my Badmo barrels. I take a tare weight of the barrel wet and empty before I fill it, then can easily determine current volume based on current weight and ABV.

Thats cool. I've done the same thing on my Badmos, but I had to do it the hard weigh. (pun intended)
I proofed the spirits then weighed 100ml to get the weight per ml, then did the math.
The proof calculator is nice, Ive always used the TTBs spreadsheet, so this will be quicker.

Here's a calculator I use for my alcoholmeters that are calibrated at 20°C/68°F
https://hobbybrennen.ch/Rechner/en/Alco ... ction.html
Also shows measured and corrected density

Very nice. Good find.

Could someone confirm that I'm using table 4 properly?

I have a badmo that I filled with 208 oz of 125 proof bourbon 2+ years ago. I have probably taken 12-16 oz for sampling over that time, and I'm sure that I've lost some to the angels as well.

I weighed an empty bain-marie (1045 g, no head), then emptied the badmo into that bm and weighed it again, subtracting 1045 g.
The weight was 4093 grams, or 9.0235 lb, and it measured 67% ABV or 134 proof. (I also measured tare weight of the badmo for future use)

From table4 134 proof is 0.17935 proof gallons per pound, so I multiply that by 9.0235 lb to get 1.618 proof gallons (1.618 gal @ 100 proof)

Now for my confusion:
That number (1.618) is 207+ oz, which isn't possible (because it was originally 208 oz), so it represents volume @ 100 proof, right? (1 proof-gallon is 1 gallon at 50% ABV)
So to get final volume at 134 proof I need to divide that by 1.34 (134/100), right?

1.618/1.34 = 1.21 gal, or 155 oz.

So now the badmo contains 155 oz, so I've lost 53 oz in 2+ years, but the proof has increased from 125 to 134. (that is equivalent to 166 oz @ the original barreling proof of 125)

Does this sound right?

higgins wrote: ↑Fri Sep 20, 2024 11:28 am Could someone confirm that I'm using table 4 properly?

I have a badmo that I filled with 208 oz of 125 proof bourbon 2+ years ago. I have probably taken 12-16 oz for sampling over that time, and I'm sure that I've lost some to the angels as well.

I weighed an empty bain-marie (1045 g, no head), then emptied the badmo into that bm and weighed it again, subtracting 1045 g.
The weight was 4093 grams, or 9.0235 lb, and it measured 67% ABV or 134 proof. (I also measured tare weight of the badmo for future use)

From table4 134 proof is 0.17935 proof gallons per pound, so I multiply that by 9.0235 lb to get 1.618 proof gallons (1.618 gal @ 100 proof)

Now for my confusion:
That number (1.618) is 207+ oz, which isn't possible (because it was originally 208 oz), so it represents volume @ 100 proof, right? (1 proof-gallon is 1 gallon at 50% ABV)
So to get final volume at 134 proof I need to divide that by 1.34 (134/100), right?

1.618/1.34 = 1.21 gal, or 155 oz.

From the calculator I linked, 64% ABV has a density of 0.9kg/L.
That would mean your 4093g=4.093kg/0.9kg/L = 4.55L/3.785L/gal = 1.2 gal, so I would say you're using the chart right.

tjsc5f wrote: ↑Fri Sep 20, 2024 1:49 pm ...
From the calculator I linked, 64% ABV has a density of 0.9kg/L.
That would mean your 4093g=4.093kg/0.9kg/L = 4.55L/3.785L/gal = 1.2 gal, so I would say you're using the chart right.

Thanks, tj ... that sure is easier than the way I did it. I've downloaded a table of concentrations in kg/l into my spreadsheet, so now I can just divide grams by density to get ml.