Grayson_Stewart wrote:3.1415 x 1" = length of one inner coil = 3.14"
3.1415 x 1.75" = length of one outer coil = 5.49"
For a 5" long coil there would be 5"/.25" individual coils, or 20 coils of each.
[20 x 3.14"] + [20 x 5.49"] = 172.6"
172.6" / 12" = 14.38 ft of tubing required.
This does not account for the run of tubing used to reach the inlet and exit water supply.
1" = 2.54 cm
I basically did the same exercise except I worked backwards instead.
I figured on using 20' of 1/4" tubing.
Diameter x pi for the outer coil + diameter x pi for the inside coil.
I figured 2 turns per inch rather than 4 to allow for 1/4" spacing. For a 5" coil, it would take 10 turns for each coil.
In this case if I wanted 10' of tubing, I would add 3.14" to 5.49" for a factor of 8.63".
10' or 120" divided by 8.63" would give the number of wraps.
120/8.63= 13 wraps with about 8" remaining for connections or 12 wraps with around 16" for connections.
12 wraps would make a 6" condenser.
In my case, with a 3" outer coil and 2" inner, for 20' of tubing, it took 17 wraps for each coil or just over 8".
I notched the top of the head to fit the tubes. With a spot of solder they don't rub and the condenser is kept centered.
I wanted a lid to keep out dust as well as protect the ceiling in the shed from hot air.( Speaking of hot air...) Anyways,
I used a flat piece of thin copper sheeting for the lid. I soldered a finger (dead finger?) to the bottom of the lid that sets in the middle of the condenser. The finger has a good 1/2" of clearance, so it is not a tight fit at all. The whole thing is very light and unobstructed so that with any rise in pressure, it will work as a relief valve.