Detail of the Equations used

From Distillers Wiki
Revision as of 08:20, 14 November 2022 by Uncle Jesse (talk | contribs) (Add hyperlink back to the distillation theory page)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to navigation Jump to search

For those researching this topic, this page is referenced here: [Theory: Reflux Still Design]


Equations used during Reflux Distillation Calculations

Reflux Distillation Calculations

Knowing the about the wash & column, we can calculate things like recommended min & max column diameters, the purity we expect off the top column, and how long it will take to heat up to temperature. Then, we can look at the column performance over time - how much we expect to collect from it, and how this changes (as does the column performance) over the course of the run.

I've collated all the required Physical constants, etc for water & ethanol on a data page

Min & Max Diameter

Calculate the flooding diameter, based on figure 18-38 in Perry

Minimim Flooding Diameter (call this "y") vs Maximum Flooding Diameter (call this "x")

Plotting the flooding line, I found : y = =1.4427 x2 -1.0271 x + 0.2312 where

   Ut = superficial gas velocity (m/s)
   ap = total area of packing (m2/m3 bed)
   e = fractional voids in dry packing
   g = gravitational constant = 9.8067 m/s2
   G' = gas mass rate (kg/s.m2)
   L' = liquid mass rate (kg/s.m2)
   rg and rl = gas and liquid densities (kg/m3)
   ml = liquid viscosity, m Pa.s (cP)

Through the top section we have

   V = vapour flowrate (kg/s)
   D = distillate (kept) flowrate (kg/s), and
   L = liquid flowrate (kg/s)

Based on the composition of the wash, and the power input (Q distill), you can estimate the amount of vapour you are generating (V in kg/s)

Q distill = (V * %ethanol * Hvap ethanol) + (V * %water * Hvap water)

Then G' = V / column area ( pD2)

The amount of liquid (L) being refluxed will depend on the Reflux ratio; since D=V-L, and the Reflux ratio is L/D, then

Reflux Ratio

So then L' = L / column area

(hmmm.. this is where I do something a little bit dodgy... we are estimating the amount of vapour being generated off the wash. This will be true for the bottom of the column, but may not be quite the same as the vapour flowrate at the very top - some of the water will have been removed from it, and it will have picked up some more alcohol vapour on the way ... So what I do is a wee mass balance based on the expected purity at the top. This can get you into a catch 22 - because you don't know this until you can work out the HETP for the packing, but you need this value to calculate the HETP.. so guess a final %, run through the calcs, see what the top % actually is, and adjust from there & recalculate if necessary).

So... calculate out x =Maximum Flooding Diameter, solve for y, then work out Ut

Since Ut = G' / area of column, and knowing area = p D2 you can solve for D Flood

This is the flooding diameter - eg smaller than this will cause the vapour flowrate to be too fast to allow the liquid to drain down past it. It is the absolute minimum diameter.

So the column needs to be a little wider. Standard recommendations are to use approx 65% the flooding velocity, so scale up the diameter we should use by

65% Flooding Velocity

Likewise, if the column is too wide, there won't be enough interaction between the liquid and the vapour. I can't find any recommendations for this, but I'm guessing about 25% would be about it, so :

25% Flooding Velocity

Now the flow rates of Liquid & Gas will be different at different heights of the column... so once you've been through the whole exercise, redo this calculation a couple of times, at a couple of different heights (flow rates). You find out that the differences aren't really worth worrying about.

HETP (Height Equivalent to a Theoretical Plate)

eg how much height of packing is needed to get the same performance as a theoretically perfect (equilibrium) plate. I've done the estimate using Onda's method (from Coulson, Richardson & Sinnott "Chemical Engineering").

Calculate the effective area (aw) using :

Effective Area

Where:

   aw = effective interfacial area of packing per unit volume (m2/m3)
   a = actual area of packing per unit volume (m2/m3)
   sc = critical surface tension for the particular packing material (see table below)
   sL = liquid surface tension mN/m
   L*w = mass flowrate per unit cross-sectional area, kg/m2s = L'
Critical surface tension
Material sc [mN/m]
Ceramic 61
Metal (steel) 75
Plastic (polyethylene) 33
Carbon 56

Then calculate the liquid and gas mass transfer coefficients (kL and kG) using :

Liquid and Gas Coefficient kL Liquid and Gas Coefficient kG

where:

   K5 = 5.23 for packing sizes >15mm and 2.0 for sizes <15mm
   V*w = gas mass flowrate per cross-sectional area [kg/m2s] = G'
   dp = packing size [m]
   kL = gas film mass transfer coefficient,[kmol/m2s atm or kmol/m2s bar]
   kG = liquid film mass transfer coefficient [kmol/m2s or kmol/m3 = m/s depending on whether use R=0.08206 atm.m3/kmol K or R=0.08314 bar m3/mol K]

From these you can then calculate the film transfer heights:

Film Transfer Heights 1

Film Transfer Heights 2

Where:

   P = column operating presure, [atm or bar]
   Ct = total concentration, kmol/m3 = r L / molecular weight solvent
   Gm = molar gas flowrate per unit cross-sectional area, kmol/m2s
   Lm = molar liquid flowrate per unit cross-sectional area, kmol/m2s

From these you can then estimate the height of the overall gas-phase transfer unit:

Height of Overall Gas-Phase Transfer Unit

Where:

   m = slope of the equilibrium line (I reckon its about 0.49)
   Gm/Lm = slope of the operating line

Equilibrium Line and Operating Line


Now... for a section of the packed column in which the operating and equilibrium lines can be considered straight (hey- that's almost us !), theoretical stages can be converted to numbers of transfer units by :

Theoretical Stages

and then

Packed Bed Heights and Number of Theoretical Stages

where:

   Zp = packed bed height
   Nt = number of theoretical stages

Mass Balance

Once you have worked your way through this, the rest is pretty much straight forward ..

Estimate the purity at the top of the column by stepping off the correct number of theoretical stages on the Equilibrium diagram

Equilibriam Diagram

I'm still working on a suitable correlation to use to describe the equilibrium line, but at present I use (x & y as %alcohol by volume (as a fraction, eg 0.15 not 15%)) ( and don't believe beyond 95% ish) :

y = -31.065 x6 + 116.08 x5 - 169.95 x4 + 123.99 x3 - 47.195 x2 + 9.1398 x

So... pick a suitable time-step, then calculate the volume removed (flowrate * time). You know the purity of it, so you can then update the total removed, the aggregate purity, and the purity and volume of the wash left in the pot.

For each time-step you can then go back to the start and redo it all again (HETP etc) if you really want to....but its not really worth the effort, as these don't change much.

Just keep a good track of the various units you're using, cos there's a bit of switching between moles, kgs, and grams along the way (let alone dabbling in Imperial units...).

Tony Ackland, 3 June 2000