https://www.mathcelebrity.com/mixture.p ... %2BMixture
How many units of % Solution 1 must be mixed with units of % Solution 2 to get a mixture that is %
How many units of a 8.25% solution must be mixed with 1.5 units of +42.2% to get +28% mixture?
Step 1:
Let x = Number of units of Solution 1
0.0825x + 1.5 x 0.422 = 0.28(x + 1.5)
0.0825x + 0.633 = 0.28x + 0.42
Subtract +28x from both sides of the equation to isolate x:
8.25x + 0.633 - 0.28x = 0.28x + 0.42 - 0.28x
Subtract 0.633 from both sides of the equation:
-0.1975x + 0.633 - 0.633 = 0.42 - 0.633
-0.1975x = -0.213
Divide each side of the equation by -0.1975
x
-0.1975
=
-0.213
-0.1975
x = 1.0784810126582
1.08G of 8.25% added to the 1.5G @ 42.2 will give me a 27% final solution. Pretty cool, huh?